Originally posted by tomzarbo
View Post

The regulator in your link is not a buck inverter. It's the common LM7812 linear regulator (despite the offers description). Other than it doesn't provide isolation, it would work. You would be reducing 24 V to 12 V, a 12 V drop through the regulator. At 0.5 A that will produce 6 W of heat in the regulator. With the heat sink, the LM series are good for up to 15 W.. But it will get hot. Imagine a couple of nightlights throwing off heat inside your enclosure.
This Link is to a true buck regulator, pictured below. This is not an isolated regulator. At 85% to 90% conversion efficiency, you could expect less than 1 W of dissipated heat. And the chip, LM2596, will be hot to the touch as it doesn't use a heat sink.
Leave a comment: