Re: 6Db. crossovers????

No,no, no. You said you added a pole to the B2 HP (woofer) response. So the poles of the B2 remain fixed. So you are just cascading the B2 HP with a B1 HP to add the third pole. This will not ever yield a Be3 as the other point I was going to make was that a Be3 HP does not have poles at +/- 45. They are at +/-43.65. So adding a single pole doesn't result in a Be3 HP. Close, but not a BE response. You would need to shift the poles of the woofer alignment too by adding a zeros to cancel the existing poles and then new poles as required. By the way, the topic of canceling zeros and poles with poles and zeros was covered in my text books from back in 68. If they aren't teaching that at GT they must be slacking off.

And again, you must be thinking of impulse response, not square wave. Further more, the truth is that the impulse response of a 3rd order Bessel HP will ring more than a 2nd order Butterworth HP, though neither is significant.

Your 2nd to 3rd order conversion, as you are applying it is nothing more than cascading a B1 with a B2.

Now, all these responses are under damped and therefore the impulse response is a damped oscillation that decays exponentially as time goes to infinity. It is not 2 cycles or 3 cycles. Further more, the true B3 as well as the B2 cascaded with a B1 initially undershoot and then overshoot more than the B2. I.e. they ring more than the B2.

Originally posted by

**moron#99**View PostNo,no, no. You said you added a pole to the B2 HP (woofer) response. So the poles of the B2 remain fixed. So you are just cascading the B2 HP with a B1 HP to add the third pole. This will not ever yield a Be3 as the other point I was going to make was that a Be3 HP does not have poles at +/- 45. They are at +/-43.65. So adding a single pole doesn't result in a Be3 HP. Close, but not a BE response. You would need to shift the poles of the woofer alignment too by adding a zeros to cancel the existing poles and then new poles as required. By the way, the topic of canceling zeros and poles with poles and zeros was covered in my text books from back in 68. If they aren't teaching that at GT they must be slacking off.

And again, you must be thinking of impulse response, not square wave. Further more, the truth is that the impulse response of a 3rd order Bessel HP will ring more than a 2nd order Butterworth HP, though neither is significant.

Your 2nd to 3rd order conversion, as you are applying it is nothing more than cascading a B1 with a B2.

Now, all these responses are under damped and therefore the impulse response is a damped oscillation that decays exponentially as time goes to infinity. It is not 2 cycles or 3 cycles. Further more, the true B3 as well as the B2 cascaded with a B1 initially undershoot and then overshoot more than the B2. I.e. they ring more than the B2.

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